ya if ur doin honours there different than the pass ones cuz 4 pass eres 1:
solve the equation:x2-3x-10=0
get d factors ov -10 (-5+2,+5-2,-10+1,+10-1) and remember for a minus number,the factors will always have one plus and one minus!4 plus it could either be two pluses or two minuses,but never different signs!
PICK THE CORRECT SET OF FACTORS WHERE YOU MULTIPLY THEM,YOU GET D NUMBER BEFORE THE x(in this case the number is 3,nd the correct set of factors is -5+2)
sub in d factors and you wil get : x2-5x+2x=0.
you will then factorise nd den get (x-5)(x+2)=0.
Then,take out the 0 and you will b left wit (x-5)(x+2).
Then,you change the sign in front of each number,and u have your equation solved!!
So,the final answer is x=5,x=-2,which is written usually as x=5,-2.
Sorry if this is confusing but hey!!if it helped ne1 let me know.good luck with these!!TAKEN FROM THE 2004 OL EXAM PAPERS q.5(c)(i)
REMEMBER IF I HAVE MADE A MISTAKE PULL ME UP ON IT IM NOT PERFECT!!